@digit mmm how did you do the third one it reminds me of something i have seen

@CobaltVelvet In all of them, I take the original IFS for the centered triangle, but I compose each function with a non-linear transform

For the third image, it's this one (p1 and p2 are parameters, with values 0.67 and -0.58)

@CobaltVelvet (for more info about the IFS formulation of the triangle : https://larryriddle.agnesscott.org/ifs/siertri/siertri.htm)

@CobaltVelvet You may have simpler ways to create this kind of pattern though ; these experiments just applies non linear transforms randomly to the IFS, in order for me to quickly discard combinations that are not worth investigating